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Physics ICSE Class 10 CBSE CUET

Work, Power & Energy – ICSE Class 10 Physics

📅 Published: June 2026

Yo! Before we start — this chapter is literally the easiest scoring one in ICSE Physics if you get the basics right. I scored 94 in Physics this year and let me tell you, this chapter alone got me around 12-15 marks in the board exam. The derivations look scary at first but trust me, once you write them 2-3 times, they just stick. Let's crack this together!

1) Work — What Does It Actually Mean?

So here's the thing. In our daily life, "work" means anything that requires effort — studying, lifting bags, even just thinking about what to eat. But in Physics? Nope. Physics has a very specific definition.

Work is said to be done only when a force applied on a body produces displacement in the body.

I remember in class my teacher kept saying: "No displacement, no work!" And honestly, that's the golden rule. If you push a wall until you're sweating but the wall doesn't move — in Physics terms, zero work. Disappointing, right? 😅

The Formula (This is your bread and butter)

W = F × s × cos θ W = work done (Joules, J) F = force applied (Newton, N) s = displacement (metre, m) θ = angle between force and displacement

Special Cases of θ — Memorise These!

θ cos θ Work Example
0° 1 W = Fs (maximum positive) Pushing a box forward — force and displacement same direction
90° 0 W = 0 (zero work) Coolie carrying luggage on head — force upward, displacement horizontal
180° -1 W = -Fs (negative work) Friction acting opposite to motion. Brakes stopping a car
θ between 0° and 90° positive W positive Pulling a suitcase at an angle
θ between 90° and 180° negative W negative Lifting a bucket from a well — gravity does negative work
The "coolie carrying luggage" example is ICSE's FAVOURITE. Every single year there's a 1 or 2 mark question asking why the work done is zero. The answer: force is perpendicular to displacement (θ = 90°). Just memorize this.
In the numericals, always first figure out what θ is. Most mistakes happen because students forget to check the angle. Draw a quick diagram if you're confused — it takes 5 seconds and saves 2 marks.

2) Energy — The Ability to Do Work

Energy is basically the capacity to do work. If something has energy, it can do work. And here's the cool part — when you do work on an object, its energy changes. They're two sides of the same coin.

SI unit of energy: joule (J). Same as work. Makes life easier.

3) Kinetic Energy (KE) — Energy of Motion

Any moving object has kinetic energy. A speeding car, a flying bird, a ball you just threw — they all have KE. The faster it moves and the heavier it is, the more KE it has.

K.E. = ½ mv² m = mass (kg), v = velocity (m/s)

Derivation of KE — Don't Skip This!

Look, I know derivations feel boring at first. But in ICSE boards, the 2-mark "derive the expression for kinetic energy" question is guaranteed. It appears almost every year. Here's a really simple way to remember it:

Step 1: Start with the work done to bring a body from rest to velocity v.

Step 2: Work done = Force × displacement.

Step 3: Use F = ma and Newton's third equation of motion.

We know: Work done = F × s Using Newton's 2nd law: F = ma Using 3rd equation of motion: v² - u² = 2as Since body starts from rest, u = 0 So v² = 2as → s = v²/2a Now substitute: W = m × a × (v²/2a) W = ½ mv² This work done on the body = Kinetic Energy gained ∴ K.E. = ½ mv²

See how clean that is? Write this 2-3 times and you'll never forget it. The trick is in those two equations — F = ma and v² = 2as. Join them and boom, you're done.

4) Potential Energy (PE) — Energy of Position

Potential energy is the energy stored in a body because of its position or configuration. There are different types, but for ICSE Class 10, we focus on gravitational potential energy.

P.E. = mgh m = mass (kg), g = acceleration due to gravity (≈ 9.8 m/s² or 10 m/s²) h = height above ground (m)

Derivation of PE — Another Free 2 Marks!

This one's even simpler. I used to mess it up until a friend showed me this trick. Just think: when you lift something up, you're doing work against gravity. That work gets stored as potential energy. That's literally it.

To lift a body of mass m to height h: Force required = mg (to overcome gravity) Displacement = h Work done = Force × displacement W = mg × h This work gets stored as potential energy ∴ P.E. = mgh
In numeric problems, pay attention to g = 9.8 or 10. ICSE usually tells you which value to use, but if they don't, use 10 m/s² to make calculations easy. I used to always write "Take g = 10 m/s²" at the start and it made my life so much easier.

5) The Law of Conservation of Energy

"Energy can neither be created nor destroyed. It can only be transformed from one form to another."

This is one of those statements that sounds simple but is SO important. What it means is that the total energy in an isolated system always stays constant. It just changes forms.

The Classic Example — A Ball Dropped from Height

This is the most common question in ICSE. At any point during the fall:

Total energy at any point = PE + KE = constant At height h: mgh + 0 = mgh At ground: 0 + ½ mv² = mgh ∴ ½ mv² = mgh → v = √(2gh)

This formula v = √(2gh) is incredibly useful. ICSE asks this in so many forms — finding speed just before hitting ground, finding height from speed, etc. If you memorize just this one relationship, half the numericals are done.

6) Power — How Fast Work is Done

Work and energy tell us how much work is done, but they don't tell us how quickly. That's where power comes in.

Power is the rate of doing work. Or in simpler words — how much work gets done per second.

P = W / t P = Power (Watt, W) W = Work done (J) t = Time taken (s)

Also, since W = F × s:

P = (F × s) / t = F × (s/t) = F × v P = F × v

This one formula — Power = Force × velocity — is a lifesaver in numericals. If a question gives you force and speed, you can directly find power in one step. No need to find work and time separately.

SI Unit of Power

Don't confuse kW and kWh! kW is a unit of power (rate), kWh is a unit of energy (total amount). This is the #1 mistake students make. I've literally lost marks on this in my pre-boards.

7) Commercial Unit of Energy — kilowatt-hour (kWh)

In our electricity bills, we don't pay in joules — we'd need HUGE numbers for that. Instead, we use kilowatt-hour (kWh).

1 kWh is the energy consumed when a device of power 1 kW runs for 1 hour.

Energy (kWh) = Power (kW) × Time (h) 1 kWh = 1000 W × 3600 s = 3.6 × 10⁶ J

So if you see a 100 W bulb running for 10 hours: energy consumed = 0.1 kW × 10 h = 1 kWh = 1 "unit" on your electricity bill.

ICSE loves asking conversion questions: "Convert 2 kWh to joules." Just multiply by 3.6 × 10⁶. If you forget the number, remember: 1 kW = 1000 W, 1 h = 3600 s, so 1 kWh = 1000 × 3600 = 3.6 × 10⁶. You can always figure it out.

8) Difference Between Work, Energy and Power — Tabular Form

This is a VERY common 2-mark question. Write it in table format in your exam for extra marks. I wrote exactly this in my board exam.

Work Energy Power
Work done = Force × displacement × cos θ Energy is the capacity to do work Power is the rate of doing work
SI unit: joule (J) SI unit: joule (J) SI unit: watt (W)
Work = change in energy Energy = ability to do work Power = work / time
Can be positive, negative, or zero Always positive (magnitude) Always positive (rate)

9) Solved Numericals — The Fun Part 💪

Alright, let's actually solve some real ICSE-level problems. These are the types that actually come in the exam. I've included a mix of easy and tricky ones.

Numerical 1 — Basic Work Calculation

A force of 50 N acts on a body and displaces it by 5 m. Calculate the work done when the force is: (a) in the direction of displacement (b) at 60° to the displacement

Given: F = 50 N, s = 5 m (a) θ = 0°, cos 0° = 1 W = Fs = 50 × 5 = 250 J (b) θ = 60°, cos 60° = 0.5 W = Fs cos θ = 50 × 5 × 0.5 = 125 J

See how the work is less when the force is at an angle? That's why pulling something at an angle is "easier" in terms of force, but less work goes into horizontal displacement.

Numerical 2 — Kinetic Energy

A car of mass 800 kg is moving with a speed of 72 km/h. Find its kinetic energy. If the driver applies brakes and the car stops after 50 m, find the force applied by the brakes.

Part 1: Speed = 72 km/h = 72 × 5/18 = 20 m/s KE = ½ mv² = ½ × 800 × (20)² = ½ × 800 × 400 = 160000 J = 1.6 × 10⁵ J Part 2: Work done by brakes = Change in KE W = 0 - 160000 = -160000 J (negative means work done against motion) W = F × s → -160000 = F × 50 F = -3200 N (negative sign means force is opposite to motion) ∴ Braking force = 3200 N
Always convert km/h to m/s by multiplying with 5/18. This is such a common mistake. 72 km/h = 20 m/s. If you remember just this one conversion (72 → 20), you'll never mess up speed conversions.

Numerical 3 — Potential Energy + Conservation of Energy

A stone of mass 2 kg is dropped from a height of 20 m. Find its potential energy at the top, kinetic energy just before hitting the ground, and its velocity just before impact. (Take g = 10 m/s²)

Given: m = 2 kg, h = 20 m, g = 10 m/s² PE at top = mgh = 2 × 10 × 20 = 400 J Just before ground: PE = 0 (since h = 0) By conservation of energy: KE just before ground = PE at top = 400 J KE = ½ mv² → 400 = ½ × 2 × v² 400 = v² → v = 20 m/s Or directly: v = √(2gh) = √(2 × 10 × 20) = √400 = 20 m/s

That v = √(2gh) is honestly the most repeated formula in ICSE energy chapters. If you see "dropped from height", this is your go-to.

Numerical 4 — Power Calculation

A pump lifts 1000 kg of water per minute from a well 20 m deep. Calculate the power of the pump. (Take g = 10 m/s²)

Given: m = 1000 kg, h = 20 m, t = 1 min = 60 s Work done = mgh = 1000 × 10 × 20 = 200000 J Power = Work / time = 200000 / 60 = 3333.33 W Power = 3.33 kW (approximately)

Numerical 5 — Energy in kWh (Electricity Bill Style)

A household uses four 60 W bulbs for 5 hours a day, a 100 W refrigerator running 24 hours a day, and a 2 kW heater running 2 hours a day. Calculate the total energy consumed in one day in kWh.

Energy = Power (kW) × Time (h) Bulbs: 4 × 60 W = 240 W = 0.24 kW, time = 5 h Energy by bulbs = 0.24 × 5 = 1.2 kWh Refrigerator: 100 W = 0.1 kW, time = 24 h Energy by refrigerator = 0.1 × 24 = 2.4 kWh Heater: 2 kW, time = 2 h Energy by heater = 2 × 2 = 4 kWh Total energy per day = 1.2 + 2.4 + 4 = 7.6 kWh

10) Quick Revision — What to Remember the Night Before the Exam

If you're reading this the night before your exam (no judgement, I've been there 😅), here's the absolute minimum you need:

Common Mistakes That Cost Marks (I made them so you don't have to)

My last advice: This chapter is one of those where if you understand the concept, every numerical is just applying the same 3-4 formulas. Don't panic. Write down the given values first, figure out what formula connects them, and solve step by step. You've got this. The 93.4% didn't come from being a genius — it came from being consistent and not giving up. Good luck! 🙌

11) Important Formulas — All in One Place

Work: W = Fs cos θ Kinetic Energy: KE = ½ mv² Potential Energy: PE = mgh Conservation of Energy: PE + KE = constant Velocity from height: v = √(2gh) Power: P = W / t = Fv Energy in kWh: E (kWh) = P (kW) × t (h) 1 kWh = 3.6 × 10⁶ J 1 hp = 746 W Speed conversion: km/h × 5/18 = m/s
Written by
Asad Abdullah
ICSE 93.4% · 2026
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